X^2+4x-2=(x-1)(x+5)

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Solution for X^2+4x-2=(x-1)(x+5) equation: 



X^2+4X-2=(X-1)(X+5)

We move all terms to the left:

X^2+4X-2-((X-1)(X+5))=0

We multiply parentheses ..

X^2-((+X^2+5X-1X-5))+4X-2=0



We calculate terms in parentheses: -((+X^2+5X-1X-5)), so:

(+X^2+5X-1X-5)

We get rid of parentheses

X^2+5X-1X-5

We add all the numbers together, and all the variables

X^2+4X-5

Back to the equation:

-(X^2+4X-5)



We add all the numbers together, and all the variables

X^2+4X-(X^2+4X-5)-2=0

We get rid of parentheses

X^2-X^2+4X-4X+5-2=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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